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serious [3.7K]
4 years ago
7

What is the area of this figure?

Mathematics
1 answer:
Andreyy894 years ago
7 0

Answer:

388

Step-by-step explanation:

First you have to do the equation to solve the area of a triangle. we ha ve 8 x 16 / 2 = 64 then we do the area of the rectangle 18 x 18 = 324      

324 + 64 = 388

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snow_tiger [21]
\frac{1}{2}(4x-2)(2x+12)=(2x-1)(2x+12)=4x^2+24x-2x-12= \\ =\boxed{4x^2+22x-12}  \ \ cm^2
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4 years ago
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A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro
Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the  playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

                                                          =2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]    

=$[2(x+y)]  

But the neighbor will play one third of the side x foot.

So the neighbor will play  =\$(\frac13x)

Now homeowner's total cost for the material is

=\$[ 2(x+y)-\frac13x]

=\$[2x+2y-\frac13x]

=\$[2y+x+x-\frac13x]

=\$[2y+x+\frac{3x-x}{3}]

=\$[2y+x+\frac{2}{3}x]

=\$[2y+\frac53x]

\therefore C(x)=2y+\frac53x  

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

                                           =xy square foot

∴xy=200

\Rightarrow y=\frac{200}{x}

Putting the value of y in C(x)

\therefore C(x)=2(\frac{200}{x})+\frac53x

The domain of C is(0,\infty ).

\therefore C(x)=2(\frac{200}{x})+\frac53x

Differentiating with respect to x

C'(x)= - \frac{400}{x^2}+\frac53

Again differentiating with respect to x

C''(x) = \frac{800}{x^3}

To find the critical point set C'(x)=0

\therefore 0= - \frac{400}{x^2}+\frac53

\Rightarrow \frac{400}{x^2}=\frac{5}{3}

\Rightarrow x^2 =\frac{400\times 3}{5}

\Rightarrow x=\sqrt{240}

\Rightarrow x=15.49 \approx15.5

Therefore

\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in y=\frac{200}{x} we get

\therefore y=\frac{200}{15.5}

    =12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

                                             

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3 years ago
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Amanda [17]
The answer is B because 7 does not evenly fit into 71 so the first box is 10 and the second box is .14285714285714or is simplified.143 or .14
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What is the volume of this right triangular prism?
Dominik [7]

The volume of the given right triangular prism can be found by first calculating the area of the right triangle and then multiplying it with the length of the prism.

Let us find the area of the right triangle. As can be seen from the diagram the height, h of the right triangle is 7 cm and the base, b of the right triangle is 4 cm.

Therefore, the area of the triangle is:

Area=\frac{1}{2}\times b\times h=\frac{1}{2}\times 4\times 7=14 cm^2

Thus, the volume of the right triangular prism will be:

Volume=Area x Length of the prism

Volume=14\times 10.3=144.2 cm^3

Thus, out of the given options, option A is the correct option.

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Answer:

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Step-by-step explanation:

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