Question

(2x^2+10x+8) divided(2x+2)

Answer 1

Answer:

x + 4

Step-by-step explanation:

$\mathrm{Factor}\:2x^2+10x+8:\quad 2\left(x^2+5x+4\right)\\=\frac{2\left(x^2+5x+4\right)}{2x+2}\\\mathrm{Factor}\:2x+2:\quad 2\left(x+1\right)\\=\frac{2\left(x^2+5x+4\right)}{2\left(x+1\right)}\\=\frac{x^2+5x+4}{\left(x+1\right)}\\\mathrm{Factor}\:x^2+5x+4:\quad \left(x+1\right)\left(x+4\right)\\\mathrm{Cancel\:the\:common\:factor:}\:x+1\\=x+4$

Hope this helps and have a great day!