Question

Angle 0 is in the second quadrant, and sin 0=3/5

Answer 1

ANSWER


The value of theta in the second quadrant is,

$143.1 \degree$


EXPLANATION

The given trigonometric equation is
$\sin( \theta) = \frac{3}{5}$


This implies that,


$\theta= arcsin(\frac{3}{5} )$


This implies that the principal solution is
$\theta = 36.9 \degree$
and it is an angle in the first quadrant.

But the solution we are looking for is an angle in the second quadrant.



This is given by
$180 - \theta = 180 - 36.9 = 143.1 \degree$