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Aleksandr [31]
3 years ago
15

Angle 0 is in the second quadrant, and sin 0=3/5

Mathematics
1 answer:
Aneli [31]3 years ago
8 0
ANSWER


The value of theta in the second quadrant is,

143.1 \degree


EXPLANATION

The given trigonometric equation is
\sin( \theta)  =  \frac{3}{5}


This implies that,


\theta=  arcsin(\frac{3}{5} )


This implies that the principal solution is
\theta =  36.9 \degree
and it is an angle in the first quadrant.

But the solution we are looking for is an angle in the second quadrant.



This is given by
180 -  \theta = 180 - 36.9 = 143.1 \degree
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