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2 years ago

Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b

1 answer:

3 0

$\32a^3b^2 \ , \ 44ab^3 \ , \ 40a^2b\\
$

$\text {Taking out common factor : } \\ \\
4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)$

$\text { greatest common factor = } 4ab$

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Fractorise the following (a-b)²+(a-b)

Lisa [10]

Step-by-step explanation:

taking common (a-b)

so we get the answer

5 0

2 years ago

Kavi solved the system

Marianna [84]

Answer:

She should have substituted y = 17 - 2x in the first equation

Step-by-step explanation:

3x + 4y = 33

2x + y = 17

y = 17 - 2x

3x + 4(17 - 2x) = 33

3x + 68 - 8x = 33

5x = 35

x = 7

y = 17 - 2(7)

y = 3

x = 7, y = 3

Only one solution

6 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

2 years ago

What is the value of x? (There should be an image)

skad [1K]

Answer:

Step-by-step explanation:

6 0

1 year ago

Solve the system of equations.

MAXImum [283]

Answer:

D. (-2, -6) and (5,15)

Step-by-step explanation:

When you set the equations together, you get x^2-3x-10. You then set this equation equal to zero and get (x-5)(x+2) or x=-2 and x=5. Then, plug these x-values into each equation to get your y-values.

8 0

2 years ago