3 years ago

Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b

1 answer:

3 0

$\32a^3b^2 \ , \ 44ab^3 \ , \ 40a^2b\\
$

$\text {Taking out common factor : } \\ \\
4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)$

$\text { greatest common factor = } 4ab$

You might be interested in

There are 4 types of the questions on Mrs. Moore's English final exam. The percent of each type of the question is shown in the

Verdich [7]

Jesse, to answer this, we need to see the graph. I'd help if I could! You can message me if you post it! :D

7 0

3 years ago

You dont have to answer but I will give you brainliest

andrezito [222]

Answer:

thanks

Step-by-step explanation:

7 0

3 years ago

Please help answer correctly !!!!!!!!! Will mark Brianliest !!!!!!!!! URGENT

krek1111 [17]

Answer:

5 00000

Step-by-step explanation:

bc it just is lolllllll

7 0

3 years ago

Approximate the area under the curve over the specified interval by using the indicated number of subintervals (or rectangles) a

RideAnS [48]

Split up [1, 3] into 4 subintervals:

[1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

each with length (3 - 1)/2 = 1/2.

The right endpoints $r_i$ are {3/2, 2, 5/2, 3}, which we can index by the sequence

$r_i=1+\dfrac i2$

with $1\le i\le4$ .

Evaluating the function at the right endpoints gives the sampling points $f(r_i)$ , {27/4, 5, 11/4, 0}.

Then the area is approximated by

$\displaystyle\int_1^3f(x)\,\mathrm dx\approx\frac12\sum_{i=1}^4f(r_i)=\frac12\left(\frac{27}4+5+\frac{11}4+0\right)=\boxed{\frac{29}4}$

5 0

3 years ago

Lashed year palm tickets were $65, and this year they are $50. What is the percent of decrease in the price of prom tickets? Rou

Goshia [24]

23% would be the answer

6 0

3 years ago

Read 2 more answers