D(.75+.5)= time run over a number of days
You only have to add the total time run together per day and multiply it by the total days run
Answer:T5GLKOIPK6
Step-by-step explanation:JIUTIUGITNG
<h3>
Answer:</h3>
63.64%
<h3>
Step-by-step explanation:</h3>
7/11 = 7/11 × 100% = (700/11)% ≈ 63.64%
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<em>Comment on fractions involving 11</em>
1/11 is the 2-digit repeating decimal 0.09090909...
So, any multiple of 1/11 is a 2-digit repeating decimal with the two digits being the numerator times 9.
Here, we have 7/11, so the 2-digit repeat is 7·9 = 63. That is ...
... 7/11 = 0.63636363...
Answer:
a. 16%
Step-by-step explanation:
The difference from the mean is ...
(x - µ) = 4420 lb -3550 lb = 870 lb
Then the minimum Z-score of the traffic of interest is ...
(x - µ)/σ = (870 lb)/(870 lb) = 1
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The "empirical rule" tells you that 68% of a normal distribution is within 1 σ (Z = ±1) of the mean. If 68% is inside that range, then the remaining 32% is outside that range. The normal distribution is symmetrical about the mean, so half that quantity is below Z = -1, and the other half, 16%, is above Z=1.
About 16% of the cars have weights more than 4420 pounds.