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![▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪](https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%20%20%7B%5Chuge%5Cmathfrak%7BAnswer%7D%7D%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA)
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The Correct choice is :
<h3><u>Explanation</u> :</h3>
As per given in the question, both the lines are parallel so they have equal slopes. that is slope of required line is :
now, let's use slope and the coordinates of the given points to find the equation of line in point - slope form :
therefore , the correct choice is A
Answer:
Step-by-step explanation:
A) Use the distributive property to eliminate parentheses. Then combine like terms. (The only "like terms" are the constants.)
... = 12 +3·2y +3·(-3) . . . use the distributive property to multiply each term in parentheses by the factor 3 outside those parentheses
... = 12 +6y -9 . . . . . . . . simplify
... = 6y + (12 -9) . . . . . . group like terms together
... = 6y + 3 . . . . . . . . . . simplify
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B) Look for factors of each term that are also found in the other term.
... 18b has factors 3×6×b
... 12 has factors 2×6
The only common factor is 6, so we factor that out using the distributive property.
... 18b -12 = 6(3b -2)
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<em>Comment on factoring</em>
For factoring problems, it helps immensely if you know your times tables and some of the rules for divisibility. (Even numbers are divisible by 2, numbers ending in 0 or 5 are divisible by 5, numbers whose sum of digits is divisible by 3 are divisible by 3, for example.)
Answer:
44°
Step-by-step explanation:
The secant- secant angle y is half the difference of the measure of its intercepted arcs, that is
(BHF - CGJ ) = y , that is
(156 - CGH) = 56° ( multiply both sides by 2 )
156 - CGH = 112° , thus
CGH = 156° - 112° = 44°
9514 1404 393
Answer:
(1.43, 1.87)
Step-by-step explanation:
The formula for the incenter requires we know the lengths of the sides of the triangle. These are found using the distance formula.
BC = √((4-3)^2 +(5+1)^2) = √37
AC = √((-4-3)^2 +(2+1)^2) = √58
AB = √((-4-4)^2 +(2-5)^2) = √73
Then the incenter is ...
(A(BC) +B(AC) +C(AB))/(BC +AC +AB)
≈ (6.08276(-4, 2) +7.61577(4, 5) +8.54400(3, -1))/22.2425
≈ (1.42808, 1.87480)
Rounded to hundredths, the incenter is (1.43, 1.87).