On the board, your teacher shows an example of finding the range.

Mathematics

1 answer:

Paladinen [302]3 years ago

3 0

Answer:

I think answer is B or C or D

Step-by-step explanation:

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Identify the rule that could possibly describe this set of data.

docker41 [41]

Answer:

D.) y=10-2x

Step-by-step explanation:

this is in slope intercept form. so its usually y=mx+b.

m is the slope

b is the y intercept

so its usually y=-2x+10. but y=10-2x also works too.

7 0

3 years ago

Find all the missing elements. Round to the nearest tenth. PLEASE HELP ME ASAP!!!

Nutka1998 [239]

C/sinB = 8/sinC
c/sinB=8/0.64
c/sinB=12.5
c=12.5*0.34
c=4.25

8*8+4.25*4.25=a^2
64+18.06=a^2
82.06=a^2
a=sqrt(82.06
a=9.05

4 0

3 years ago

Find the equation of the line that is perpendicular to the line y = (-1/3)x -1 and passes through the point (1, 5)?

Anit [1.1K]

bearing in mind that perpendicular lines have negative reciprocal slopes, so

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{1}{3}}x-1} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{1}\implies 3}}$

so we're really looking for a line whose slope is 3 and runs through (1,5)

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=3(x-1) \\\\\\ y-5=3x-3\implies y=3x+2$