Answer:
Step-by-step explanation:
X = whole number
Z = fraction numarater
Y = fraction denometer
you can do
X = X/1
Z and Y = Z/Y
X/Z = C(the new numartater)
Y/1 = Y
C/Y
Answer:
I think maybe the 4th one
Equailateral means that base=40mm
solve for height
split the triangle in half with a line perpendicular to the base
now you have 2 right triangles with base 40/2=20 and hypotonuse 40
solve for height or the other side
use pythagorean theorem
a^2+b^2=c^2
20^2+b^2=40^2
400+b^2=1600
subtract 400 fromb oth sides
b^2=1200
square root boht sides
b=√1200=20√3
the height =20√3
area of triangle=1/2base times height
base=40
height=20√3
1/2 times 40 times 20√3=20 times 20√3=400√3
the area is 400√3 mm^2
4(2x - 1) + 3(2x + 5)
8x - 4 + 6x + 15
14x + 11 (the answer).
3, 1, -1, -3, -15 (the 10th term)
Let me know if you need working on this part :)