Question

Correct answers only!! Circle P is described by the equation (×+4)^2 + (y+7)^2 = 16 and circle Q is described by the equation (x+2)^2 + (y-3)^2 =25. Select from the drop-down menus to correctly complete the statements. Circle Q is ( 2, 4, 6, or 10) units to the (left or right) of circle P and (2, 4, 6, 10) units (above or below) it. Circle Q has (a shorter radius, the same radius as, or a longer radius then) circle P.

Answer 1

Answer:

Circle Q is 2 units to the right of circle P and  10 units above it.

Circle Q has a longer radius than circle P.

Step-by-step explanation:

The equation for the circle P is $(x+4)^2 + (y+7)^2 = 16$

Its center is in (-4,-7) and the radius is $r=\sqrt{16} =4$

The equation for the circle Q is $(x+2)^2 + (y-3)^2 =25$

Its center is in (-2,3) and the radius is $r=\sqrt{25} =5$

Subtracting (-2,3)-(-4,-7)=(2,10)

The center of Q is 2 units to the right of the center of P and is 10 units above.

The radius of Q is longer than the radius of P