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3 years ago

Find the quotation -10/-5= need help ASAP

Mathematics

2 answers:

natita [175]3 years ago

7 0

Answer:

Step-by-step explanation:

eduard3 years ago

7 0

Answer: 2

Step-by-step explanation: Divide -10 and -5. When you do, the answer will be 2. If you see 2 numbers that both have a negative sign, that means in the end, your answer will be positive. That is why -10/-5 is 2.

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Which point is located on quadrant IV

pychu [463]

It's the letter D hope it helps

8 0

2 years ago

Please answer correctly !!!!!!!!!!! Will mark brainliest !!!!!!!!!!!

nikklg [1K]

Answer:

lower price = 3

higher price =11

Step-by-step explanation:

p(x) = -2(x-3) (x-11)

Setting equal to zero

0 = -2(x-3) (x-11)

Using the zero product property

x-3 = 0 x-11 =0

x=3 x = 11

7 0

3 years ago

The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that $P(A \cap B) = 0.03$

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

2 years ago

Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items,

Ivanshal [37]

Answer:

77.64% probability that there will be 0 or 1 defects in a sample of 6.

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$