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igor_vitrenko [27]
3 years ago
15

Mike traveled to Greensboro by car. Going there took 6 hours, and the return trip was four hours. Mike averaged a speed of 81 mi

les while returning. Find the average of the trip there.
Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer: 64.8 mph

Step-by-step explanation:

Given

Arriving time is 6 hours

return time is 4 hours

The average speed of returning 81 mph

Distance traveled while returning

\Rightarrow d=81\times 4=324\ miles

the average speed of the entire trip is

\Rightarrow v_{avg}=\dfrac{2\times 324}{6+4}=\dfrac{648}{10}=64.8\ mph

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A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean
Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
PLEASE HELP
Ronch [10]

Answer:

ammmmmmmmmmmmm what's the Question?

6 0
3 years ago
HELP FAST!!! MULTIPLE CHOISE!!!!!!!!!!!!!!!!!!!!!!!
liq [111]

letter C

1462 rounds up when looking at the tens place to 1500

5 0
4 years ago
Read 2 more answers
the quadratic function h (t)=-16t^2+150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15 sto
natulia [17]
Hello! Lets solve this :)
So for the first question :
h(t) = -16t^2 + 150
h(0)= -16 (0)^2 + 150
h(0)= -16(0) + 150
h(0)= 0 + 150
h(0)= 150 feet

Second question
We need to find here the time when the ball hit the ground; or when the height h(t) is 0.
In equation form
h(t) --> 0=16t^2 + 150
16t^2 = 150
t^2=150/16
t= <span>√150/16
t= 5</span><span>√6/4
t= 5 (2.45)/4
t= 3.06 seconds
</span>
Hope this helps! If you have any other questions or would like further explanation just let me know! :)



3 0
4 years ago
The answers to (a)-(d) work is not needed just answers
Debora [2.8K]
A)  n(a) = 25 + 15 = 40
b) n(b) = 42+15 =57
c) n (a U b) = 25 +15+ 42 = 82 
d) n (a') = 42
e) n(b') = 25
f)  n(a intersection b)' =  82-15 = 67 
g) n (a U b)' =     14 
h)  n (a'  intersection  b') =  14
i)  n (a' U b') = 42 + 25 +14 = 81 


hope i helped a bit .. :-)
6 0
3 years ago
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