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igor_vitrenko [27]
3 years ago
15

Mike traveled to Greensboro by car. Going there took 6 hours, and the return trip was four hours. Mike averaged a speed of 81 mi

les while returning. Find the average of the trip there.
Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer: 64.8 mph

Step-by-step explanation:

Given

Arriving time is 6 hours

return time is 4 hours

The average speed of returning 81 mph

Distance traveled while returning

\Rightarrow d=81\times 4=324\ miles

the average speed of the entire trip is

\Rightarrow v_{avg}=\dfrac{2\times 324}{6+4}=\dfrac{648}{10}=64.8\ mph

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June had $240 more than Siti. Junr gave 25% of her money to Siti. Siti then gave 20% of her money to June. How much more money d
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Answer:

$144

Step-by-step explanation:

Let the money which Siti has be x

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Siti's money = x+ [25%(x+240)]       June's money = x+240-[25%(x+240)]

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Second condition is that Siti now gave 20% of her money to June.This amount will be deducted form Siti's money and added in June's money.

Siti's money = 1.25x+60-[20%(1.25x+60)]    

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June's money = 0.75x +180+[20%(1.25x+60)]

                        = x+192

Difference between Sitit and June's money = x+192-x-48

                                                                        = 144

Hence, June has $144 more money than Siti.

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