Answer:
10
Step-by-step explanation:
Square = 2 x 2 = 4
The Small triangle is half of the square so 4 divided by 2 is 2.
The big triangle 4 x 2 = 8 divided by 2 is 4.
So,
4 + 2 + 4 = 10
19. What you know is that HK+KJ = HJ. If HJ = 25, the sum of the two equations will equal this length.
x-5+5x-12=25 First, combine your like terms. You will end up with 6x-17=25. Add the opposite of -17 to both sides. 6x = 42 Divide both sides by 6. x = 7. Substitute x=7 for your original expression of x-5, 7-5=2
20. (5x-6)/2 = x+6 Multiply each side by 2. 5x-6 = 2x +12 Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well. 3x = 18 Finally divide each side by 3. x=6 To find the length of the remaining segment, substitute this value into (5x-6)/2. This results in each side equaling a distance of 12.
21. On the number line, the distance of FG is 16 units. If the distance of FP is 1/4 of FG, you would simply divide 16 by 4. The distance of FP is 4 and P lies at 8 on your number line.
23. The distance of SP is x+4 and ST=4x. Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x. Balance and solve for x, subtract 2x from both sides. 8=2x Divide each side by 4, 8/4 = 4x/4 resulting in x=2. If ST equals 4x, substitute and solve, 4(2) = 8
Let
A-----> 
B-----> 
C-----> 
we know that
Point A-------> Multiply numerator and denominator by 

Point B-------> Multiply numerator and denominator by 

Point C-------> Multiply numerator and denominator by 

Find the distance Point A to Point C

Find the distance Point B to Point C

therefore

Point B is closer to Point C
is closer to 
the answer is
is closer to 
Answer: non-linear 40 1/2 Step-by-step explanation: This is a non-linear function specifically it is an oscillating function The initial position of the weight occurs at t=0 and from the graph we see that at t=0, the weight position is 40 centimeters The weight is said to reach equilibrium when its position is at 0 cm. From the graph we can see that the function first reaches 0 cm at t=0.5 seconds or at t= 1/2 second
Step-by-step explanation:
hope this helps theirs 3 pictures