Answer:
Step-by-step explanation:
There would be 4 + 4 + 4 = 12 angles formed by a transverse intersecting three parallel lines
Answer:
(a): Marginal pmf of x


(b): Marginal pmf of y


(c): Mean and Variance of x


(d): Mean and Variance of y


(e): The covariance and the coefficient of correlation

Step-by-step explanation:
Given
<em>x = bottles</em>
<em>y = carton</em>
<em>See attachment for complete question</em>
<em />
Solving (a): Marginal pmf of x
This is calculated as:

So:






Solving (b): Marginal pmf of y
This is calculated as:

So:






Solving (c): Mean and Variance of x
Mean is calculated as:

So, we have:




Variance is calculated as:

Calculate 




So:




Solving (d): Mean and Variance of y
Mean is calculated as:

So, we have:




Variance is calculated as:

Calculate 




So:




Solving (e): The covariance and the coefficient of correlation
Covariance is calculated as:

Calculate E(xy)

This gives:




So:




The coefficient of correlation is then calculated as:





--- approximated
The base of the triangle is x² + 2x + 4
The height of the triangle is 2x² + 2x + 6
The area of the triangle is
A = (1/2) b h
Substituting
A = (1/2)(x² + 2x + 4)(2x² + 2x + 6)
Which can be expanded or factored
Answer:
<em><u>10.8</u></em><em><u>°</u></em><em><u>degrees</u></em>
Step-by-step explanation:
<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☻</u></em><em><u>♨️</u></em><em><u>♨️</u></em><em><u>☻</u></em><em><u>☺️</u></em><em><u>❤</u></em>
Answer:
30% because the chance of the whole dice is 6