Question

An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of r(t) = 85e−0.04t liters per minute. How much oil leaks out during the first hour? (Round your answer to the nearest liter.)

Answer 1

Given the rate of water flow is given by:
r(t)=85e^(-0.04t)
thus the amount of water flow in the first hour when t=1, will be:
r(1)=85e^(-0.04*1)
=81.667
thus the amount of water that flowed out will be:
85-81.667
=3.333 liters