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2 years ago

5 over 7 or 3 over5

Mathematics

2 answers:

alekssr [168]2 years ago

7 0

Answer:

5/7 or 3/5

Step-by-step explanation:

Sorry if I'm wrong bc I don't understand the question

Igoryamba2 years ago

7 0

Yes. There is no accurate question to be answered. If this is a riddle, I do not think it counts. I apologize.

I am joyous to assist anyone at any time though.

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If 0 < x < 1 and 0 < y < 1, which of the following must be true?

katovenus [111]

0<x<1 and 0<y<1

x>0 so x is positive and y>0 so y is also positive.
When you multiply two positive numbers you always get a positive number, so the product of x and y must be positive, or greater than 0.
xy>0 - it must be true
xy<0 - it can't be true
Also when you divide a positive number by a positive number you always get a positive number, so the quotient of x and y must be positive.
x/y<0 - it can't be true
D and E can be true, but don't have to. It depends on the values of x and y. If x>y, then x-y>0 is true and x-y<0 isn't true; if x<y, then x-y>0 isn't true and x-y<0 is true.

Therefore, only A must be true.

3 0

3 years ago

5.28 rounded to the nearest tenth

Bond [772]

$5.28\to\boxed{5.30}$

5 0

2 years ago

Read 2 more answers

Quick! Anyone know this geometry question?

WARRIOR [948]

The correct answer is C.

5 0

2 years ago

Read 2 more answers

1.Simplify 5 to the 5th over 5 to the 8th.

timurjin [86]

Q1. The answer is 1 over 5 to the 3rd power.

5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is $\frac{ 5^{5} }{ 5^{8} }$
To simplify, we will use two rules:
$\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}$
Therefore:
$\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}$
$\frac{1}{5^{3}}$ is the same as 1 over 5 to the 3rd power.

Q2. The answer is (53)−4.

The exponents are multiplied when are expressed in the form:
 $(x^{a}) ^{b}= x^{a*b}$
So, $(5^{3} )^{-4}=5^{3*(-4)}=5^{-12}$

Other choices are incorrect:
one third to the 4th times one third to the 7th is $( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}$
3 to the 7th over 3 to the 15th is $\frac{ 3^{7} }{3^{15}} =3^{7-15}$
45 ⋅ 42 is $4^{5}* 4^{2} = 4^{5+2}$

3 0

2 years ago

Read 2 more answers

(help please due today)

Viktor [21]

For 11 on the dot plot its only supposed to be 2 dots because u only see two 11’s the mean is 78/15 which equals 5.2 the mode is 5 the range is 11-1 which equals 10

3 0

2 years ago

5 over 7 or 3 over5​

5 over 7 or 3 over5