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3 years ago

Whats (x + 3) - (5x - 4)

Mathematics

2 answers:

djverab [1.8K]3 years ago

8 0

Answer:

the answer is −4x+7

Step-by-step explanation:

yes

quester [9]3 years ago

7 0

Answer:

-4x+7

Step-by-step explanation:

(x+3)-(5x-4)

Remove parenthesis and simplify:

-4x+7

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Solve mathematics question: In photo:) Second:)

mojhsa [17]

Hello,

Answer D

A Slopes :5/8,12/5==> no product is not -1

B:slopes: -1/2,3 no

C:slopes:2,-1/3 no

D:slopes:-3/2,2/3 Yes product=-1

6 0

3 years ago

Read 2 more answers

The value of the expression a³-2a²+3a+5 for a = -1

mrs_skeptik [129]

Answer:

- 1

Step-by-step explanation:

Substitute a = - 1 into the expression, that is

(- 1)³ - 2(- 1)² + 3(- 1) + 5

= - 1 - 2(1) - 3 + 5

= - 1 - 2 - 3 + 5

= - 6 + 5

= - 1

4 0

3 years ago

Read 2 more answers

Line segment AB is the diameter of circle C. If the endpoints of the diameter are (3, -4) and (7,2), what are the coordinates of

dimulka [17.4K]

Answer:

(5, -1)

Step-by-step explanation:

You find the center of both the coordinates. For the x axis: 3+7 = 10. 10/5=2. For the y axis: -4+2=-2. -2/2 = -1. Put them together and get the answer! :)

5 0

3 years ago

Solve using quadratic equation: 6x^2 + 7x +2=0

Alika [10]

Step 1: Factor left side of equation.

(3x+2)(2x+1)=0

Step 2: Set factors equal to 0.

3x+2=0 or 2x+1=0

x=−23 or x=−12

Answer:

x=−23 or x=−12

3 0

3 years ago

g An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b

Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn Red Ball Blue Ball Total Ball

1 4 6 10

2 16 x 16+x

Getting a red ball from first urn is $P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{4}{10}$

Getting a blue ball from first urn is $P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {6}{10}$

Getting a red ball from second urn is $P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{16}{16+x}$

Getting a blue ball from second urn is $P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {x}{16+x}$

Getting two red balls from first and second urn is $=\frac{4}{10}\times \frac{16}{16+x}$

$=\frac{32}{5(16+x)}$

Getting two blue balls from first and second urn is $=\frac{6}{10}\times \frac{x}{16+x}$

$=\frac{3x}{5(16+x)}$

The probability that both balls are the same in color is $=\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}$

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

$\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44$

$\Rightarrow \frac{32+3x}{5(16+x)} =0.44$

$\Rightarrow \frac {32+3x}{(80+5x)} =0.44$

$\Rightarrow 32+3x =0.44(80+5x)$

$\Rightarrow 32+3x =35.2 +2.2x$

$\Rightarrow 3x -2.2 x= 35.2 -32$

$\Rightarrow 0.8x= 3.2$

$\Rightarrow x = 4$

Therefore the of blue in the second urn is 4.

5 0

3 years ago