Answer: Hello!
Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)
We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.
The total number of permutations is the product of the number of options that you have for each letter, this is:
17*16*15*14*....*3*2*1 = 17! = 3.6e+14
(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is
30! = 2.65e+32
(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.
then P = 47! = 2.59e+59
(d) DERMATOGLYPHICS: here are 18 letters, then:
p = 18! = 6.4e+15
-0.72 , -5/8 , -0.6 , -7/12
Answer:
7y - 4x
Step-by-step explanation:
Given
- 3(2x - y) + 2y + 2(x + y) ← distribute parenthesis
= - 6x + 3y + 2y + 2x + 2y ← collect like terms
= 7y - 4x
Answer: 2 markers.
Step-by-step explanation:
1. You know that she gives 12 markers to Mr. Cooke, then the rest among is:
29 markers-12 markers=17 markers
2. She divides the rest among 5 other teachers and each one of them get the same number of markers. So, you need to divide 17 markers by 5 teachers as following:
17 markers/5=3.4 markers
3. But the number of marker each one teacher has can't be a decimal number, so this number must be: 3 markers for each teacher.
3. The number of markers that will be left over is:
17 markers-(5*3 markers)=2 markers
