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3 years ago

4x²-6xy PLZ HELP I GIVE 5 STARS

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

yep I get the same thing what the other person is right

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P(0,-1) that is parallel to the line y= -2x+3

Mandarinka [93]

Answer:

y=2x+3

A parallel line is only supposed to have an oposite slope.

3 0

3 years ago

A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove

Anna11 [10]

Answer:

The amount lost over the 3 years s 2567.25£

Explanation:

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

6 0

3 years ago

Simplify 90/105. show work.

Marina CMI [18]

90/105... divide the top and bottom by 5 so you get 18/21 then divide by 3 so you get 6/7 or just divide by 15 at the beginning and get 6/7. The answer is 6/7

6 0

4 years ago

Solve the equation. pls help

Lyrx [107]

Answer:

y=-3

Hope this helps!

7 0

3 years ago

Public opinion in the large city of Bedrock is that 60 percent of the residents are in favor of increasing taxes to fund alterna

uysha [10]

Answer: 0.8461

Step-by-step explanation:

Let p be the proportion of residents are against the increase of taxes to fund alternatives to drug addiction treatment.

As per given , we have p=0.40

A random sample is taken with size : n= 400

Expecting sample proportion : $\hat{p}=\dfrac{150}{400}=0.375$

Now , the probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed will be :

$P(p>0.375)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})$

$=P(z>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})\ \ [\because\ z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]$

$=P(z>-1.02)=P(z-z)=P(Z$

$\approx0.8461$ [By z-table]

Hence, the approximate probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed is 0.8461 .

4 0

4 years ago