Answer:
38.4
Step-by-step explanation:
(multiply) hkssfejshwjwjgwskfhkdshejkdhdc (don't mind the random letters it needed to be 20 characters)
Answer:
155 minutes
Step-by-step explanation:
1. Find the total available "computer time": 4 hours * 12 computers= 48 hours
2. Split this among all of the students: 48 hours/25 students= 1.92 hours
3. Convert to minutes: 1.92 hr/student * 60 minutes ≈ 155 minutes/student
Answer:
The missing exponent is 15.
Step-by-step explanation:
<h2><u><em>
Brainliest Please!</em></u></h2>
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
F(x)=5x-26 is your correct answer