<h3>
Answer: (x+1)(x+3)</h3>
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Explanation:
Let's assume it factors into (x+a)(x+b)
The goal is to find the two numbers a and b.
FOIL out (x+a)(x+b) to get x^2+(a+b)x+ab
Note how a+b is the middle term and ab is the last term.
In the original expression, 4 is the middle term and 3 is the last term.
So we need to find two numbers that
There are two ways to multiply to 3 and they are
- 1 times 3 = 3
- -1 times -3 = -3
But only the first way has the factors add to 4. So that means a = 1 and b = 3.
Therefore (x+a)(x+b) = (x+1)(x+3)
And x^2+4x+3 = (x+1)(x+3)
Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
There's an app called photomath that would be useful for these kinds of problems!
Answer:
30.25 & 33.25
Step-by-step explanation:
x² + 11x + (5.5)² = 3+ (5.5)²
x² + 11x + 30.25 = 33.25
Step-by-step explanation:
x2-8x-3x+24=0
x(x-8) 3(x+8)
(x-8)(x+8)
x-8=0 or x+8=0
x=8. x= -8
