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2 years ago

A) y=1.1x+23 B) y=1.25x+20 C) y=1.25+40.67 D)y+1.4+40.67

Mathematics

1 answer:

Lunna [17]2 years ago

7 0

Answer:

I believe C is the correct answer because the graph starts above 40 on y axis and D is incorrect because of the y + not y=

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3 + 1 < 10 solve, then graph the solution

ryzh [129]

3 + 1 < 10

There's no question there, and nothing to solve. That's a simple statement
which, after simplifying it slightly, says " 4 < 10 ".

A statement with which, I'm sure, we can all agree.

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3 years ago

I'll give brainlest <3

AleksandrR [38]

45 maybe bc it’s small

3 0

2 years ago

Read 2 more answers

Find the area of the equilateral triangle when the base is 2.0 cm and the top angle is 50°

nordsb [41]

Answer:

There is an error in the question.

All angles in an equilateral triange are 60º

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2 years ago

n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

3 0

3 years ago

Help as fast as u can

lyudmila [28]

I believe the answer to your question is going to be

D) g(x)=(x+3)^2

Hope I’m correct!

8 0

2 years ago