3 years ago

Help me pls number 4 I’m giving brainlest

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Answer:

hi:) you can use an app called photomath, you just take a picture of any math problem and it gives you the answer and shows all the work:) thats what I use.

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Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+

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The vertex form of the equation of a parabola is given by

$y-k=a(x-h)^2$

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

$y-(-2)=a(x-(-12))^2 \\ \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\ \\ y=ax^2+24ax+114a-2 \\ \\ y=x^2+24x+ \frac{114a-2}{a}$

For a = 1,

$y=x^2+24x+112$

<span>The parabola whose minimum is at (−12,−2) is given by the equation $y=x^2+ax+b$ , where a = 24 and b = 112.</span>

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3 years ago

Evaluate log12y2, given log12y = 16.

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Step-by-step explanation:

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