Answer:
The solution should be log7^3(49)-1/3log7(49)=1/3*2
B-2/3
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Area of the triangle = 1/2 * base * <span>height
base = 16 in
</span>height = 16 in
Area = 1/2 * 16 * 16 = 128 in.
I know its a long problem but i have to shiw how i got my answer.
Step-by-step explanation:
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