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Vladimir [108]
3 years ago
13

16235 to the nearest ten thousand

Computers and Technology
2 answers:
masha68 [24]3 years ago
7 0
16235 to the nearest ten thousand would be 20,000.

Hope this helps :)
~ Davinia.
Anna35 [415]3 years ago
4 0
16200 is to the nearest ten thousand
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Mention five importance of taskbar​
sveticcg [70]

Answer:

The taskbar is an element of an operating system located at the bottom of the screen. It allows you to locate and launch programs through Start and the Start menu, or view any program that's currently open.

6 0
3 years ago
Identity theft, where people steal personal information, continues to be a problem for consumers and businesses. Assume that you
svetlana [45]

Answer:

Secure the personal information with complex multi-factor authentication and configure intrusion detection and prevention and a firewall.

Explanation:

Multi-factor authentication is a method of securing a client's personal information from the client's side to the data centre. It uses more than one security processes not policies. There key be three authentications process like a password, security token and biometrics or two authentications like password and biometrics or token.

The firewall and intrusion detection and prevention are vulnerability preventive method to detect and stop cyber attacks.

5 0
3 years ago
Write a program to read a list of exam scores given as integer percentages in the range 0-100. Display the total number of grade
Tju [1.3M]

Answer:

import java.util.Scanner;

public class Program

{

  public static void main(String [] Args)

  {

      int totalAGrades = 0, totalBGrades = 0, totalCGrades = 0, totalDGrades = 0, totalFGrades = 0, counter=0,maximum = 0, minimum = 9999, num, total = 0,smallest = 0,largest = 0;

       Scanner in = new Scanner(System.in);

       System.out.println("Enter exam percentage: ");

       System.out.println("Enter a negative examScore: ");

       int examScore = in.nextInt();

       while(examScore > 0)

       {

         counter++;

         if(examScore < 0){          

             break;}  

         else if(examScore > maximum){      

              maximum = examScore;}

         else if(examScore < minimum)   {  

              minimum = examScore;}

         

          total = total + examScore;  

     

          if(examScore <= 50 && examScore>0)

              smallest = examScore;

              if(examScore > 90 && examScore <=100)

              largest = examScore;

         

      if(examScore>=90 && examScore<=100)

          totalAGrades++;

      else if(examScore>=80 && examScore<=89)

          totalBGrades++;

      else if(examScore>=70 && examScore<=79)

          totalCGrades++;

      else if(examScore>=60 && examScore<=69)

          totalDGrades++;

      else if(examScore>=0 && examScore<=59)

          totalFGrades++;

      examScore = in.nextInt();

     

   }

      System.out.println("Total number of scores is = " + counter );

      System.out.println("Total Number of each Letter grade : " + counter);

      System.out.println("Percentage of total for each letter grade : ");

          System.out.println("Total number of A grades = "+ totalAGrades);

          System.out.println("Total number of B grades = "+ totalBGrades);

          System.out.println("Total number of C grades = "+ totalCGrades);

          System.out.println("Total number of D grades = "+ totalDGrades);

          System.out.println("Total number of F grades = "+ totalFGrades);

     

      System.out.println("Lowest exam Score is :"+smallest);

      System.out.println("Highest exam Score is :"+largest);

      System.out.println("Average exam Score = "+ (total / counter));

  }

}  

Explanation:

  • Get the exam information from user as input and run a while loop until examScore is greater than zero.
  • Use conditional statement to check the scores of students and increment the relevant grade accordingly.
  • Finally display all the information including grades and scores.
3 0
3 years ago
Suppose you wanted to run a web server or ftp server from your home. what type of ip address would you want?​
Greeley [361]
You would need to have a static ip address.
3 0
3 years ago
Write a recursive function to compute sum of first N integers starting with 1.
Citrus2011 [14]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// recursive function to find sum from 1 to n

int recur_Sum(int n)

{ // base condition

if (n <= 1)

 return n;

// recursive call

return n + recur_Sum(n - 1);

}

// main function

int main()

{

   // variables

   int n;

   cout<<"Enter a number:";

   // read the number

   cin>>n;

   // print the sum

   cout<<"Sum of first "<<n<<" integer from 1 to "<<n<<" is:"<<recur_Sum(n);

return 0;

}

Explanation:

Read a number from user and assign it to variable "n".Call function recur_Sum() with parameter "n".This function will recursively call itself and find the Sum of first n numbers from 1 to n.Then function will return the sum.

Output:

Enter a number:10

Sum of first 10 integer from 1 to 10 is:55

4 0
3 years ago
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