<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
Answer = 8y
Step-by-step explanation:
if an octagon has 8 sides and each side is = to y then the total side length in the primiter is = to 8sides times y or 8y
Answer:
midpoint formula: (x₁ + x₂)/2, (y₁ + y₂)/2
distance: √[(x₂ - x₁)² + (y₂ - y₁)²]
Step-by-step explanation:
What points are you trying to calculate the distance and the midpoint for?
in parallelogram EFGH
the mid point of diagonal EG is
(-3-5)/2,(1+5)/2=(-4,3)
similarly the midpoint of diagonal FH is
(0-2)/2,(2+6)/2=(-1,4)
The slope of p is 3
the slope of q is -3