<h3>
Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.
6.2 you subtract the 0.7 from 6.9 because 0.7 of it is milk chocolate
Answer:
522
Step-by-step explanation:
The assumption is that the proportion of tagged fish caught is the same as the proportion of all fish that were caught and tagged:
(all fish)/(number tagged) = (sample size)/(number in sample tagged)
all fish = (number tagged) · (sample size)/(number in sample tagged)
all fish = 174 · 39/13
all fish = 522
If all the assumptions are reasonable, the number of fish in the lake is estimated at 522.
Answer:
1/root(3)
Step-by-step explanation:
the steps are in the pic above.