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3 years ago

How can you use geometry figures to solve real world problems

1 answer:

5 0

In engineering its got to be used when making buildings and stuff like that. Even when making computers or cars, you got to make parts. Shapes and measurements are huge parts of that. Its also important for model designs. Geometry is used everywhere. Lets say you are trying to figure out the logo sign for a new business you are setting up in town. You are trying to figure out the size, shape, and where to put it on the building. Anything involving creation, such as fashion, technology, engineering, etc., uses geometry as a guide in the process of making something. I don't know if this was the answer you were looking for, but this was my understanding of the question. Hopefully this helps.

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PLZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPP

vodomira [7]

Answer:

Both the radius and height of the cylinder are 2.48 cm.

Step-by-step explanation:

V = π r2 h

(where r is the radius and h is the height.)

However, in the problem statement, we were told that the radius equals the height or "r = h"

So, we can rewrite the above equation as:

V = π r2*r = π r3

Now we just have to solve for r

r3 = V/π

r = (V/π)1/3

r = (48/π)1/3=2.48 cm

8 0

3 years ago

Read 2 more answers

A medium 1 topping pizza costs $12, and each additional topping costs $0.50. Don paid $16.50 for a medium pizza. If x gives the

Paladinen [302]

Answer:

A: 12+ 0.50x

Step-by-step explanation

4 0

3 years ago

An airplane descends from an altitude of 32,000 feet above sea level to an altitude of 27,000 feet above sea level.

igomit [66]

he descends -5000 ft. because 32,000-27,000 is 5000 and the plane is going down so the answer is -5000

3 0

4 years ago

Factor each expression p²+11pq+24q²

LiRa [457]

(p+3q)(p+8q) is your answer

5 0

3 years ago

Let V be the vector space P3[x] of polynomials in x with degree less than 3 and W be the subspace

Pepsi [2]

By definition, the span of two vectors is the set of all possible linear combinations of said vectors. So, any element in W is obtaining by choosing two numbers a,b and building

$a(7-8x-8x^2)+b(x^2-(5+6x)) = -8ax^2-8ax+7a+bx^2-6bx-5b$

(a)

So, you can show a nonzero polynomial in W by choosing any values of a and b, as long as they're not both zero. To keep it as simple as possible, we can choose for example a=1, b=0 and we obtain one of the base vectors of W:

$7-8x-8x^2$

(b)

Factoring the powers of x, we see that a generic polynomial in W looks like

$(b-8a)x^2-(8a+6b)x+7a-5b$

So, we must build a polynomial

$dx^2+ex+f$

such that it is not possible that

$\begin{cases}d=b-8a\\e=8a+6b\\f=7a-5b\end{cases}$

For example, let's try the polynomial $x^2+x+1$

We should solve the system

$\begin{cases}b-8a=1\\8a+6b=1\\7a-5b=1\end{cases}$

And you can check that it has no solutions. So, the polynomial $x^2+x+1$ does not belong to W. On the other hand, it surely belongs to V, because it is a polynomial with degree less than 3. So, the polynomial $x^2+x+1$ belongs to V/W.

7 0

4 years ago