<h3>hello!</h3>
=====================================================
Parallel lines have the same slope.
So if the given line has a slope of 3, then the line parallel to it has the same slope (3)
Now, let's write the equation of the line in Point-Slope Form.
Remember, point-slope form looks like so:-
Where
y₁ is the y-coordinate of the point that the line passes through
m is the slope
x₁ is the x-coordinate of the point that the line passes through
In this case,
y₁ is equal to -8
m is equal to 3
x₁ is equal to 1
Plug in the values:
Simplify:
and we're done!
=========================================================
<h3>note:-</h3>
Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)
Answer:
The required equation of line is y=-6x-57.
Step-by-step explanation:
The point slope form of a line is
Where m is slope of the line.
It is given that a line that passes through (–9, –3) and has a slope of –6.
Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.
Subtract 3 from both the sides.
Therefore the required equation of line is y=-6x-57.
I suppose P is a point that has coordinate -5 by OX and 12 by OY
/\ OY
|
* P(-5,12) |
|
|
|
|
|
|
|
|
|
|
|
----------|------------------------------------------>
-5 OX
Use the formula.
Area = (1/2)*13*10*sin(72°) ≈ 61.8 units².