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3 years ago

what if 5 more students respond that they get to school by biking? would more students walk or ride to school explain

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

More students would bike to school because it says "5 more" students bike to school

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Mark talked on his cell phone 3 hours over the weekend. Generic talked on his phone 1 9/10 hours. How much longer did mark talk

lubasha [3.4K]

Do 3 minus 1.9

- To make this easier I would do

3 - 2 = 1
1 + 0.1 = 1.1

8 0

3 years ago

PLEASE HELP. Quadratic Functions - Pre-Calculus 11.

ohaa [14]

Ans: The new price from each donut results in most revenue.

Work in the picture:

5 0

2 years ago

Is 1 + 4 (3x - 10) - 12 equivalent to -9

Phoenix [80]

Answer:

No.The answer should be -4.1

Step-by-step explanation:

1+4(3x-10)-12

5(3x-10)-12

15x-50-12

15x-62

x=-62/15

x=-4.1

6 0

3 years ago

In a fitness program, Pedro does 20 sit-ups on the first day, and increases this by 2 sit-ups everyday. Determine the day when t

Fittoniya [83]

Answer:

day 540

Step-by-step explanation:

He increases his number of situps by 2 each day meaning on day 1 he'd do 2 extra, on day 2 he'd do 4 extra, on day he'd do 6 extra etc. We can show this by saying +2x where x is the day he is on. Then since he started with 20 we have to add 20 so it would be 20+2x. We want to know what day it is when he does 1100 situps so we can set our equation equal to 1100 and solve for X which is the day it would be.

20+2x=1100

2x=1080

I hope this helps and please don't hesitate to ask if there is anything still unclear!

x=540

5 0

3 years ago

If the demand function for a commodity is given by the equation

Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

$p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\$

$q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13$

replace p in any equation and

$q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92$

3 0

3 years ago