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3 years ago

I have nine books and have room to display only four of them at a time on my bookself. How many different ways could I do this?

1 answer:

3 0

So to do this on paper I’d usually write out four blanks. One to represent each spot on the shelf. Then think about how many options you have for the first spot, 9. Now that you’ve used one, you second spot can only have 8 options. Since we’ve used two the third spot only has 7 options now. Finally the fourth spot has only 6 options. To get the answer we not multiply these four numbers
9x8x7x6= 3,024

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What is the solution to this equation?

hram777 [196]

Answer:

Option A

Step-by-step explanation:

x + 8 = -3

x + 8 - 8 = -3 - 8

x = - 11

6 0

3 years ago

Read 2 more answers

An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of

Helga [31]

Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = $\pi r^{2} \frac{h}{3}$

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

$r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm$

We will now find the volume of the cone.

Volume of cone $\pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}$

We know the density of ice is 0.93 grams per $1cm^{3}$

$1cm^{3} =0.93g\\\frac{168175\pi }{24} cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g$ (Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = $\pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}$

Volume of cone being melted = New Volume - Original volume

= $\frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}$

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = $\pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}$

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = $5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}$

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= $\frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}$

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

4 0

2 years ago

logan had a bank account balance of 287 he then deposit 35 and went on a shopping trip if he spends 78 what is his new balance a

gizmo_the_mogwai [7]

The answer is 244 because you add 35 to 287 then subtract 78 and it equals 244

6 0

3 years ago

In old-growth forests of douglas fir, the spotted owl dines mainly on flying squirrels. If we left When the initial population i

Delicious77 [7]

Answer: There are 667 owls for every 1000 squirrels.

Step-by-step explanation:

Since we have given that

Number of owls = 30

Number of squirrels = 45

If the number of owls and squirrels will continue to increase.

If there are 1000 squirrels, then the number of owls would be

$\dfrac{30}{45}=\dfrac{x}{1000}\\\\x=\dfrac{30\times 1000}{45}\\\\x=666.67\\\\x\approx 667$

Hence, there are 667 owls for every 1000 squirrels.

5 0

3 years ago

Find the data set that places 22.6 as an outlier.

Anon25 [30]

The data-set that places 22.6 as an outlier is given as follows:

2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9

<h3>When a measure is considered an outlier in a data-set?</h3>

A measure is considered an outlier in a data-set if it is very far from other measures, especially in these two cases:

If the measure is considerably less than the second smallest value.

If the measure is considerably more than the second highest value.

In this problem, he data-set that places 22.6 as an outlier is given as follows:

2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9.

The second highest value is 5.3, which is considerably less than 22.6, hence 22.6 is an outlier in the data-set.

More can be learned about statistical outliers at brainly.com/question/9264641

#SPJ1

8 0

1 year ago