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charle [14.2K]
3 years ago
10

I have nine books and have room to display only four of them at a time on my bookself. How many different ways could I do this?

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0
So to do this on paper I’d usually write out four blanks. One to represent each spot on the shelf. Then think about how many options you have for the first spot, 9. Now that you’ve used one, you second spot can only have 8 options. Since we’ve used two the third spot only has 7 options now. Finally the fourth spot has only 6 options. To get the answer we not multiply these four numbers
9x8x7x6= 3,024
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This section is worth 20 points. See the scoring rubric for more details on how you

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Use the evidence you gathered to tell the story of a hypothetical indigenous

community in the Americas and its experience involving the Columbian Exchange.

Come up with a community whose circumstances are typical of many in Central

America, the West Indies, or another part of the Americas that had direct contact with

Europeans. Tell the story in chronological order, but feel free to skip whole years or

decades so that you can cover each of the important topics related to the activity: the

availability of goods, the effects of disease, and the impact of European culture

(language and religion, for example), at the very least.

Think of your story as more of a summary than a work of fiction; you must cover a

large span of time in few words. Base the details of the story on factual evidence and

cite your sources, but keep in mind that the text should be written as a story, not as

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free body diagram can be used to help work out the net force acting on an object. True or, false?

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USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

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