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salantis [7]
3 years ago
12

In the triangle below, what ratio is sec H?

Mathematics
1 answer:
Maslowich3 years ago
3 0
We know that
in the right triangle FGH
cos H=adjacent side angle H/hypotenuse
adjacent side angle H=g
hypotenuse=f
so
cos H=g/f
sec H=1/cos H
sec H=1/(g/f)-----> sec H=f/g

the answer is
sec H=f/g
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