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scoundrel [369]
3 years ago
12

sanjay's dog weighs 46 pounds on earth multiply the dogs earth weight by 0.38 to find how much it would weigh on mars, and by 2.

36 to find how much it would weigh on jupiter how much less would the dog weigh on mars than on Jupiter?
Mathematics
1 answer:
Roman55 [17]3 years ago
6 0
The dog weighs 17.48 pounds on Mars and 108.56 pound on Jupiter. Therefor, it will weigh 91.08 pounds less on Mars than on Jupiter.
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Answer:

y = 4

Step-by-step explanation:

y/16 = 5/20 = 2/8

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Find the value of x in the following quadrilateral
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Answer:

The answer is 63.31

Step-by-step explanation:

2x - 5 + 3x - 42 + x +  \frac{3}{7} x = 360 \\  \frac{45}{7} x = 360 + 47 \\ x = 63.31

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Step-by-step explanation:

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andrew11 [14]

Answer:

<h3>\frac{\sqrt{24}- \sqrt{54} }{\sqrt{6}} = -1   </h3><h3>\sqrt{\frac{9}{20}*\frac{10\sqrt{2} }{3\sqrt{5} } = 1.4142</h3><h3>\frac{10\pi\sqrt{2}-8\pi\sqrt{2}}{2\sqrt{2}}  = π =3.14159</h3><h3>\pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}} = π² = 9.8696</h3>

Explanation:

1.) Rewrite √24 = \sqrt{4*6} = 2\sqrt{6}   Rewrite √54 =\sqrt{9*6}= 3\sqrt{6}

Divide both terms by the denominator; √6 cancels. 2-3 = -1

2.) Rewrite as \frac{3}{2\sqrt{5}} ×\frac{10\sqrt{2}}{3\sqrt{5}}  The 3's cancel.  10/2 = 5√2 in the numerator.

√5 × √5 = 5 in the denominator.  The 5's cancel.

That leaves √2 ≈1.4142

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√2's cancel.  10π/2 = 5π   8π/2 = 4π  

Subtract and we are left with π = 3.14159

4.) \pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}}  The square roots are reciprocals. They multiply to 1

We are left with π × π = π² ≈  9.8696

<h3> </h3>

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3 years ago
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