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Ulleksa [173]
3 years ago
15

Approximate, in square centimeters, the area of a circle with radius=43 cm. (Round your answer to two decimal places.)

Mathematics
1 answer:
antoniya [11.8K]3 years ago
5 0

Answer:

this is my answer for this question

21.5

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How can the bar symbol be used to show the quotient of 7÷11 if the division is carried on forever?
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\bf 7\div 11\implies 0.636363636363636........\implies 0.\overline{63}

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3x + 2 = 65 *<br> What is x
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3x = 65 - 2
3x = 63
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8 0
3 years ago
-25+t=-44 solve. Use the addition principle to find solution. T=
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To find T, you add 25 to both sides, isolating the varible. This gives you T=-19

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4 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
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