Answer:
The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Subtract 2x 2 x from both sides of the equation. Divide each term by −6 - 6 and simplify. Divide each term in −6y=12−2x - 6 y = 12 - 2 x by −6 - 6 .
Step-by-step explanation:
hope that helps
Answer:
the value after solving = 16
Step-by-step explanation:
=》8 + (8/1^4) =》8 + 8 ( since 1^4 = 1 )
=》16
Answer:
490 students have back packs
Step-by-step explanation:
700 / 10 = 70
70* 7 = 490
Answer:
see below
Step-by-step explanation:
<h3>Proposition:</h3>
Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE
<h3>Proof:</h3>
1)The lines AD and BC are parallel and AC their transversal therefore,
![\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20DAC%20%3D%20%20%5Cangle%20ACB%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
2)The lines AB and DC are parallel and BD their transversal therefore,
![\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%20%5Cangle%20BD%20C%3D%20%20%5Cangle%20ABD%20%5C%5C%20%20%5C%20%5Cqquad%20%5B%5Ctext%7B%20alternate%20angles%20theorem%7D%5D)
3)now in triangle ∆AEB and ∆CED
therefore,

hence,
Proven