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Anna [14]
3 years ago
6

What is the value of X?

SAT
2 answers:
soldi70 [24.7K]3 years ago
7 0

Answer:

x = 7

Explanation:

To solve for x in this equation, we're going to need to get the two exponents (3x - 5 and x + 1) equal to each other, but we can't do that unless our bases are the same.

For example, in A^{x} = B^{x + 1}, you cannot solve x = x + 1. In A^{x} = A^{x + 1}, you can solve x = x + 1.

Just by looking at the bases, 5 and 25, you can tell that it will be simple to make them match. 25 is just 5². The tricky part is going to be figuring out where to put the 2 into x + 1.

Let's look at another example. If you have 2^{2 * 2}, then you can simplify it to 2^{4}, which is 16. Or, you could do them one at a time, so (2^{2}) ^{2}. This way you'd have 4², which you'd be able to recognize as 16. Based on this example, we know that to make our bases the same, we need to change 25^{x + 1} to 5^{2(x + 1)}.

5^{3x-5} = 25^{x+1}   Change the right side to 5^{2(x + 1)}

5^{3x-5} = 5^{2(x+1)}   Simplify that exponent using distribution

5^{3x-5} = 5^{2x+2}  

Now that the bases match, you can get rid of them and just set the exponents equal to each other and solve for x.

3x - 5 = 2x + 2   Add 5 to both sides

3x = 2x + 7   Subtract 2x from both sides

x = 7

Now, check you work!

5^{3x-5} = 25^{x+1}   Plug in 7 for x

5^{3(7)-5} = 25^{(7)+1}   Simplify

5^{21-5} = 25^{8}   Simplify one more time

5^{16} = 25^{8}   Plug these into a calculator if you have one

152587890625 = 152587890625   So you know that x = 7 is correct.

nevsk [136]3 years ago
6 0

Answer:

<u>x = 7</u>

Explanation:

Because 25 is a perfect square of 5, we can turn

5^{3x - 5} = 25^{x + 1}

into

5^{3x - 5} = 5^{2x + 2}

Since the bases are now both equal, we can completely ignore them, as we are only trying to find x. This leaves us with:

3x - 5 = 2x + 2

All we have to do now is solve for x:

x - 5 = 2          <em>Subtract 2x from both sides.</em>

<u>x = 7</u>                <em>Add 5 to both sides.</em>

<em />

<em />

<em>Hope this helps! :)</em>

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