The Kind of file that would be the best to handle the basic calculation would be a spreadsheet.
<h3>What is a spreadsheet?</h3>
This is the term that is used to refer to the file that is made up of rows and columns. The rows and columns are made up of what is referred to as cells. Each cell contains data.
The spreadsheet is used to take care of calculations and helps majorly in statistics and accounting. Examples of spreadsheets are excel.
These sheets are able to carry out computations even up to statistical and engineering calculations. They help to make work faster and make interpretation of work easier.
The use of spreadsheets have kind of helped to make the use of lots of statistical formulas obsolete. This is because the operations are easier and faster when done on the sheets.
Read more on spreadsheets here:
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Answer:
2080 IU
Explanation:
Given
Ratio of vitamin A in cow milk to goat milk = 3 : 4
Required
Determine the content of vitamin A in goat milk if cow milk has 1560 IU
The given parameters shows a direct proportion.
Let G represents Goat and C represent Cow
Given that there exists a direct proportion;
C = K * G where K represents the constant of proportionality.
Solving for K when C = 3 and G = 4
C = K * G becomes
3 = K * 4
3 = 4K
Divide through by 4
¾ = K
K = ¾
Now, solving for G given that C = 1560IU;
We'll make use of the same formula as above
C = K * G
Substitute 1560 for C and ¾ for K; the expression becomes
1560 = ¾ * G
Multiply both sides by 4
4 * 1560 = 4 * ¾ * G
6240 = 3 * G
Multiply both sides by ⅓
⅓ * 6240 = ⅓ * 3 * G
2080 = G
G = 2080
Hence, the vitamin A in the goat milk is 2080IU
Answer:
Because Water is not a buffer solution and the acetic acid/acetate solution is a buffer solution. An acidic buffer is a solution of a weak acid (acetic acid) and its conjugate base pair (sodium acetate) that prevents the pH of a solution from changing drastically through the action of each component with incoming acid or base.
The value of 
is -3. 
<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />
We derive an expression for by means of chain rule and differentiation rule for a product of functions:
![\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5Ccdot%20g%28y%29%5D%20%3D%20%5Bf%27%28x%29%5Ccdot%20%5Cfrac%7Bdx%7D%7Bdx%7D%5D%5Ccdot%20g%28y%29%20%2B%20f%28x%29%20%5Ccdot%20%5Bg%27%28y%29%5Ccdot%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%5D)
![\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5Ccdot%20g%28y%29%5D%20%3D%20f%27%28x%29%5Ccdot%20g%28y%29%20%2Bf%28x%29%5Ccdot%20g%27%28y%29%5Ccdot%20%5Cfrac%7Bdy%7D%7Bdx%7D)
(1)
If we know that 
, 
,<em> </em>
,<em> </em>
and
, then we have the following expression:
The value of is -3.
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<h3>Remark</h3>
The statement is incomplete and full of mistakes. Complete and corrected form is presented below:
<em>The point (-2, 4) lies on the curve in the xy-plane given by the equation </em>
<em>, where </em>
<em> is a differentiable function of </em>
<em> and </em>
<em> is a differentiable function of </em>
<em>. Selected values of </em><em>, </em>
<em>, </em><em> and </em>
<em> are given below: </em><em>, </em><em>, </em><em>, </em><em>. </em>
<em />
<em>What is the value of </em><em> at the point </em>
<em>?</em>
