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crimeas [40]
3 years ago
11

What is the product of 6x-y and 2x-y+2?

Mathematics
2 answers:
Ganezh [65]3 years ago
6 0
Product = multiply

(6x-y)*(2x-y+2) =

12x^2 -8xy + 12x + y^2 - 2y


vitfil [10]3 years ago
3 0
It’s 12x^2 -8xy + 12x + y^2 - 2y
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If f(1) = 13 and f '(x) ≥ 3 for 1 ≤ x ≤ 3, how small can f(3) possibly be?
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Answer:

The answer to this question is 19.

Step-by-step explanation:

Given that :

f(x)=13.

f'(x)=3.   1 ≤ x ≤ 3.

Integrate

∫f'(x) dx=∫3 dx

f(x)=3x+c        1 ≤ x ≤ 3.

f(1)= 3+c  

c=13-3 =10.

f(x)=3x+10  1 ≤ x ≤ 3.

now ,

f(3)=3(3)+10=19.

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Which statement is true about the parentheses in this expression? [24 − (15 + 2) + 3] − 9
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Answer: 0

Step-by-step explanation:

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Amanda think of a number, a. She subtract 4 then multiples the result by 2. Write an expression for her number?
algol13
(X - 4 ) x 2 = X

You subtract X from four then you get your answer next to multiply your answer by two resulting in an answer….. the answer is the expression I wrote above.
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An account earns simple interest. (a) Find the interest earned. (b) Find the
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Answer:

#a. $80

#b. $1680

Step-by-step explanation:

We are given;

  • Amount invested (principal) is $1600
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We are required to determine the amount of simple interest earned and the amount or balance in the account after 1 year.

#a. Interest earned

To calculate simple interest we use the formula;

I = (PRT) ÷ 100

Where, P is the principal, R is the rate, T is the time and I is the simple interest.

Therefore;

I = (1600 × 5 × 1) ÷ 100

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Therefore, simple interest earned is $80

#b. Balance of the account (Amount accrued)

We are going to use the formula;

A = P + I , where A is the amount accrued, P is the principal and I is the simple interest earned.

Therefore;

Account balance = $1600 + $80

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Thus, the account balance after 1 year will be $1680

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