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OLga [1]
2 years ago
10

On his first three tests, Shaun scored 88, 98, and 79. What score must he get on his fourth test to have an average (mean) of 80

for all four tests?
Mathematics
1 answer:
solniwko [45]2 years ago
7 0

Answer:

Step-by-step explanation:

let score in fourth test=x

88+98+79+x=80×4

265+x=320

x=320-265=55

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80+90=8+9 add a 0 to the end of your answer
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Answer:

The answer is 170

Step-by-step explanation:

Because 8 + 9 = 17, if we multiply all of these values by ten or add a zero to the end of each number, we should get

80 + 90 = 170

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2 years ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

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