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KatRina [158]
3 years ago
9

Help please I will give brainliest

Mathematics
2 answers:
mestny [16]3 years ago
8 0
D. 7/23 is your answer
stepan [7]3 years ago
6 0
3 2/23, because you can do 3 times 7 is 21 and then you have 2 rest, that's the 2/23
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Which of the following expressions cannot be written as a whole number?
Allisa [31]
9^0 its that answer because all the other number you can make a whole number.
6 0
3 years ago
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Justin had 5 dogs he gave his friend 4 How many dogs dose justin have now
zloy xaker [14]
1 because he HAD 5 and if he gave his friend 4 than he has 1 left, 5-4=1 my friend.
5 0
3 years ago
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

3 0
3 years ago
Please help me on this it’s due
olya-2409 [2.1K]
<h3>Answer:  5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\

Do the same for the other mixed number 2 & 1/3.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\

-----------------------

From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\

The last step is to convert that result to a mixed number.

\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

-----------------------

Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

3 0
3 years ago
Which graph represents an odd function?<br><br>Answer by using: A, B, C, or D for each graph.
vladimir1956 [14]

Answer: The correct option is C.

Explanation:

A function is called an odd function if,

f(-x)=-f(x)

It means if the points are in the form of (x,y) then (-x,-y) is also in the graph.

Reason for correct option:

In option C, a point  (1,2),

It means,

f(1)=2

And we have another point (-1,-2).

f(-1)=-f(1)=-2

The other points are (2,3),(-2,-3),(3,-1),(-3,1),(4,0),(-4,0). Therefore the function is an odd function.

Reason for incorrect option:

In option A, a point is (1,3), therefore the value of function at x = -1 should be -3.

But the value of function is 1 at x=-1, therefore it is not an odd function.

In option B, a point is  (1,0), therefore the value of function at x = -1 should be 0.

But the value of function is -3 at x=-1, therefore it is not an odd function.

In option D, a point is (1,-1), therefore the value of function at x = -1 should be 1.

But the value of function is -1 at x=-1, therefore it is not an odd function.

6 0
3 years ago
Read 2 more answers
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