Area of the polygon defined by the given points is 62.5 sq units
Step-by-step explanation:
Step 1 :
Let P be the point (-5,0) Q = (0,-5), R = (-15,-20) and S = (20,-15)
We have to to find the area of the polygon PQRS
Step 2 :
The area of polygon given the vertices (x
is given by
Area = mod (
) ÷ 2
Where
is the vertex n's x coordinate ,
is the vertex n's y coordinate
Substituting the corresponding values ,
Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75) ) ÷ 2
= mod (25-75+0-75) ÷ 2
= mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units
Step 3 :
Answer :
Area of the polygon defined by the given points is 62.5 sq units
8^4x=135
log(8^4x)=log(135
4x*(log(8))=log(135)
4x=log(135)/log(8)
4x=2.358939
4x/4=2.358939/4
x=0.589735
The awnser is 96 because you would chose the one bigger or you wouldn't chose the one smaller so choose a medium number 96
Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
Answer:
54
Step-by-step explanation:
400-184=216
216 out of 400 turned into percentage is 54