Question

X^2+26x+48=0 What are the solutions?

Answer 1

Hi there!

Let's solve this equation step by step!
${x}^{2} + 26x + 48 = 0$

First factor the equation. To do this we're looking for two numbers with a product of 48 and a sum of 26. We find the numbers 24 and 2. Let's factor!

$(x + 24)(x + 2) = 0$
Now use the rule AB = 0 gives A = 0 or B = 0.

We find the following:
$x + 24 = 0 \: \: or \: \: x + 2 = 0$

And finally subtract.
$x = - 24 \: \: or \: \: x = - 2$

~ Hope this helps you!