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2 years ago

Write the equation of the line that passes through the points (0,-5) and (4,3)

Mathematics

1 answer:

Anettt [7]2 years ago

6 0

Answer:

Step-by-step explanation:

Gradient = y2-y1 all over x2-x1

G = 3-(-5) all over 4-0

Therefore your answer = 1/2

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What expressions represent 1/3 times the sum of 8 and 4

san4es73 [151]

Answer:

1/3 * (8 + 4)

Step-by-step explanation:

Expression which represents 1/3 tines the sum of 8 and 4

Expressing mathematically,

Sum of 8 and 4 is written as (8 + 4)

1/3 of the sum is expressed as ; 1/3 x (8 + 4)

Hence,

1/3 * (8 + 4)

1/3 * 12

= 4

Expression is 1/3 * (8 + 4)

Result = 4

8 0

3 years ago

1 is 25% of what number?

vlada-n [284]

1 is 25% of 4 hope this helps you

8 0

2 years ago

Solve. - 1/3b = 9 A. -3 B. 3 C. - 27 D. 27

ruslelena [56]

$-\dfrac{1}{3}b=9\ \ \ |multiply\ both\ sides\ by\ (-3)\\\\-3\cdot\left(-\dfrac{1}{3}b\right)=-3\cdot9\\\\\huge\boxed{b=-27}\leftarrow\boxed{C}$

3 0

3 years ago

Read 2 more answers

What is a y-intercept of the continuous function in the table?

Vadim26 [7]

Answer:

5=y-intercept

Step-by-step explanation:

the y intercept point is when y has a number but x is 0 so we see what is y (f(x)) and it is 5

5 0

3 years ago

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

3 years ago

Read 2 more answers