an institution has 500 full time students and part time students. the institution charges each full time student a $20 activity
1 answer:
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Answer:
Lola was in lead for of a mile.
Step-by-step explanation:
We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.
To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:
Therefore, Lola was in lead for of a mile.
Answer: The calculations are done below.
Step-by-step explanation:
(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,
Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.
(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,
Since, BC = CA, so the triangle ABC will be an isosceles triangle.
(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,
Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.
(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,
Since AB² + CA² = BC², so this will be a right angled triangle.
(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,
Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.
Thus, the match is done.