Answer:
or -0.42
Step-by-step explanation:
Given:
The statement says -5/8 times 2/3
Solution:



the numerator and denominator is divided by 2

Therefore, The multiplication of
and
is
or -0.42
Answer:
There are 60 permutations.
Step-by-step explanation:
Arrangements formula:
The number of possible arrangements of n elements is given by:

With repetition:
For each element that repeats, with
times, the formula is:

In this question:
Apple has 5 letters.
P appears two times. So

There are 60 permutations.
Answer:
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
Step-by-step explanation:
Let consider Q to be the opening altitude.
The mean μ = 135 m
The standard deviation = 35 m
The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:




If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.
The probability of success = 0.1587
the number of independent parachute n = 5
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:
P(R ≥ 1) = 1 - P(R < 1)
P(R ≥ 1) = 1 - P(R = 0)
The probability mass function of the binomial expression is:
P(R ≥ 1) = 
P(R ≥ 1) =
P(R ≥ 1) = 1 - 0.5785
P(R ≥ 1) = 0.4215
Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
Answer:x=10
Step-by-step explanation:
First let's create an equation:
2(x+5)+2x=50
2x+10+2x=50
4x+10=50
4x=40
x=10