Question

I need help with this problem 2(w+7)+6(3w−1)

Answer 1

Hi there!

Your equation states 2(w + 7) + 6(3w - 1)

If parentheses touch a number like 2 and 6 in your case, you would have to multiply that number with what's in the parentheses.

Let's start 2(w + 7)

2 × w = 2w

2 × 7 = 14

Combine the answers and the equation.

2w + 14 + 6(3w - 1)

Lets do the same thing with the other part.

6(3w - 1)

6 × 3w = 18w

6 × (-1) = -6

Combine the answers and the equation again.

2w + 14 + 18w - 6

Subtract 14 from both sides.

2w + 14 + 18w - 6

      -14            -14

You would end up with 2w + 18w -20

Add 2w and 18w. You could only add them because they are like terms.

2w + 18w = 20w

Combine the answer with the equation

20w - 20

Divide 20w on both sides.

20w ÷ 20w = 1

20w ÷ 20 = w

Your answer is w = 1

I hope this helped!~

Answer 2

Use distributive property: a(b + c) = ab + ac.

2(w + 7) + 6(3w - 1) = (2)(w) + (2)(7) + (6)(3w) + (6)(-1)

= 2w + 14 + 18w - 6

combine like terms

= (2w + 18w) + (14 - 6) = 20w + 8

Answer: 2(w + 7) + 6(3w - 1) = 20w + 8