Question

Determining the Axis of Symmetry of Quadratic Functions Which functions have an axis of symmetry of x = –2? Check all that apply. f(x) = x2 + 4x + 3 f(x) = x2 – 4x – 5 f(x) = x2 + 6x + 2 f(x) = –2x2 – 8x + 1 f(x) = –2x2 + 8x – 2

Answer 1

Answer:

$f(x) = x^2 + 4x + 3$

$f(x) = -2x^2 - 8x + 1$

Step-by-step explanation:

$f(x) = x^2 + 4x + 3$

To find axis of symmetry we apply formula

$x= \frac{-b}{2a}$

a= 1, b= 4

$x= \frac{-4}{2(1)}=-2$

Axis of symmetry at x=-2

$f(x) = x^2 - 4x - 5$

a= 1, b= -4

$x= \frac{4}{2(1)}=2$

Axis of symmetry at x=2

$f(x) = x^2 + 6x + 2$

a= 1, b= 6

$x= \frac{-6}{2(1)}=-3$

Axis of symmetry at x=-3

$f(x) = -2x^2 - 8x + 1$

a= -2, b= -8

$x= \frac{8}{2(-2)}=-2$

Axis of symmetry at x=-2

$f(x) = -2x^2 + 8x - 2$

a= -2, b= 8

$x= \frac{-8}{2(-2)}=2$

Answer 2

answers:

             f(x) = x² + 4x + 3, f(x) = –2x² – 8x + 1,