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m_a_m_a [10]
3 years ago
12

Determining the Axis of Symmetry of Quadratic Functions Which functions have an axis of symmetry of x = –2? Check all that apply

. f(x) = x2 + 4x + 3 f(x) = x2 – 4x – 5 f(x) = x2 + 6x + 2 f(x) = –2x2 – 8x + 1 f(x) = –2x2 + 8x – 2
Mathematics
2 answers:
Kruka [31]3 years ago
6 0

Answer:

f(x) = x^2 + 4x + 3

f(x) = -2x^2 - 8x + 1

Step-by-step explanation:

f(x) = x^2 + 4x + 3

To find axis of symmetry we apply formula

x= \frac{-b}{2a}

a= 1, b= 4

x= \frac{-4}{2(1)}=-2

Axis of symmetry at x=-2

f(x) = x^2 - 4x - 5

a= 1, b= -4

x= \frac{4}{2(1)}=2

Axis of symmetry at x=2

f(x) = x^2 + 6x + 2

a= 1, b= 6

x= \frac{-6}{2(1)}=-3

Axis of symmetry at x=-3

f(x) = -2x^2 - 8x + 1

a= -2, b= -8

x= \frac{8}{2(-2)}=-2

Axis of symmetry at x=-2

f(x) = -2x^2 + 8x - 2

a= -2, b= 8

x= \frac{-8}{2(-2)}=2

vagabundo [1.1K]3 years ago
4 0

answers:

             f(x) = x² + 4x + 3, f(x) = –2x² – 8x + 1,

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