Answer:
Above the x-axis
Step-by-step explanation:
Lets assume a polygon that has coordinates at A(3,2), B(3,4),C(6,4),D(6,2).
This polygon is in the 1st quadrant
so rotate it clockwise 90° about the origin, you apply the rule that point of object (h,k) will change to (k,-h) hence
A (3,2) ⇒A'(2,-3)
B (3,4) ⇒ B'(4,-3)
C (6,4) ⇒C' (4,-6)
D (6,2) ⇒D' (2,-6)
the image is in the 4th quadrant
Reflecting the rotated figure on the x-axis we get
A''=(2,3)
B''=(4,3)
C''=(4,6)
D''=(2,6)
it is on the 1st quadrant
The translation is(-3,3)
The image will be
A'''=(-3+2,3+3) = (-1,6)
B'''=(-3+4,3+3)= (1,6)
C'''=(-3+4,6+3)= (1,9)
D'''=(-3+2,6+3)= (-1,9)
the final figure above x-axis
Answer:
24 3/4
Step-by-step explanation: has a greater amount.
Hello!
Rolling a die and flipping a coin is Independent
The marble one is dependent
Hope this helps!
The perimeter is all the sides added up.
s1+s2+s3+s4= p
So, 12+ 6+ 8+ 17= the perimeter.
12+6+8+17 = 43
The answer is 43.
I hope this helps!
~cupcake
455.219
first of all we need to know our place values.
4= hundreds
5= tens
5= units/ones
2= tenths
1= hundredths
8= thousandths
7= ten thousandths.
To round a number to the nearest thousandth, look at the next place value to the right (the ten thousandths). If it's 4, or less, just remove all the digits to the right. If it is 5 or greater, add 1 to the digit in the thousandths place and then remove all the digits to the right.
Now to your question; the ten thousandths digit is greater than 5 (7). So we would add 1 to the digit in the thousandths place ( which is 8) then remove all digits to the right.
So our result end up in :
455.219
Please mark as brainliest.