For this case we must find the solution of the following quadratic equation:
Where:
Then, the solution is given by:
Substituting the values:
By definition we have:
Thus, we have two complex roots.
Answer:
The equation has no real roots.
A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect
1 answer:
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Given a = 3 and b = - 8 ,
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152