Answer:
can you upload a photo
Step-by-step explanation:
ANSWER

EXPLANATION
The sum of the first
terms of a geometric sequence is given by;

Where
, is the number of terms and
is the first term.
When
, we have
, we get;





1. add 40 to the 40 and 25
2. now you have

3. then you have

4. then square root

5.then round answer to nearest tenth which is
Answer:
-sin x
Step-by-step explanation:
sin(3π/3+x)=sin (π+x)=-sin x
or
sin (π+x)=sin πcos x+cos π sin x=(0)cos x+(-1)sin x=0-sin x=-sin x
Answer:
Yoko bought 5 pounds of coffee.
If you want the steps, let me know. Hope this helps!!
Step-by-step explanation: