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ki77a [65]
3 years ago
12

Please helpppppp!!!!!

Mathematics
1 answer:
azamat3 years ago
4 0
Let they meet after second car travels for x hours'
let v be the speed  of second car and V be speed of first car.
Then time taken by first car=x+2
V(x+2)=vx (distance covered is same.)
\frac{v}{V} = \frac{x+2}{x} 
subtract 1 from both sides
 \frac{v-V}{V} = \frac{2}{x} 
v-V= \frac{2V}{x}


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Step-by-step explanation:

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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}

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\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7

8 0
2 years ago
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PLEASE HELP ITS DUE SOON IM SO CONFUSED! HELP NEEDED!!
ddd [48]

Answer:

<u>e</u>

Step-by-step explanation:

According to Angle Sum Property :

<u>∠A + ∠B + ∠C = 180°</u>

<u />

============================================================

Given :

⇒ ∠A = 50°

⇒ ∠B = 32°

===========================================================

Solving :

⇒ 50° + 32° + ∠C = 180°

⇒ ∠C + 82° = 180°

⇒ ∠C = <u>98°</u>

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1) multiply across
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2) divide what’s left over.
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