The awnser is 7.47 you move the decimal over 4 spaces
Answer:
C) 37
Step-by-step explanation:
1/2(PQ)=RQ
2.5x+17=6x-11
17=3.5x-11
28=3.5x
x=8
RQ=6(8)-11
RQ=48-11
RQ=37
Answer:

Step-by-step explanation:
Given
5 tuples implies that:

implies that:

Required
How many 5-tuples of integers
are there such that
From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.
Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location
So, there are n + 4 items to make selection from
The selection becomes:



Expand the numerator




<u><em>Solved</em></u>
Answer:
c = 17
Step-by-step explanation:
Since this is a right angle triangle we can use the Pythagoras theorem that states that
(where c is the Solve for hypotenuse and "a" and "b" are the legs of the right angle triangle). From here we know that the answer to this question is....

Answer: 6
Explanation: calculator